42=-x^2+x

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Solution for 42=-x^2+x equation: 



42=-x^2+x

We move all terms to the left:

42-(-x^2+x)=0

We get rid of parentheses

x^2-x+42=0

We add all the numbers together, and all the variables

x^2-1x+42=0

a = 1; b = -1; c = +42;
Δ = b2-4ac
Δ = -12-4·1·42
Δ = -167
Delta is less than zero, so there is no solution for the equation

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